the speed of car of 500 kg increased from 20 m per second to 40 m per second how much work was done by engine of the car
Answers
Answered by
12
Work done = Change in Total energy.
therefore,
![w = \frac{1}{2} mu{ }^{2} - \frac{1}{2} m {v}^{2} w = \frac{1}{2} mu{ }^{2} - \frac{1}{2} m {v}^{2}](https://tex.z-dn.net/?f=+w+%3D++%5Cfrac%7B1%7D%7B2%7D+mu%7B+%7D%5E%7B2%7D++-++%5Cfrac%7B1%7D%7B2%7D+m+%7Bv%7D%5E%7B2%7D+)
On replacing values given,
![w = \frac{1}{2} .500. ({40}^{2} - {20}^{?} ) w = \frac{1}{2} .500. ({40}^{2} - {20}^{?} )](https://tex.z-dn.net/?f=w+%3D++%5Cfrac%7B1%7D%7B2%7D+.500.+%28%7B40%7D%5E%7B2%7D++-++%7B20%7D%5E%7B%3F%7D+%29)
So answer is
![w = 250.1200 = 300000j w = 250.1200 = 300000j](https://tex.z-dn.net/?f=w+%3D+250.1200+%3D+300000j)
therefore,
On replacing values given,
So answer is
Answered by
2
Explanation:
answer is 3×10^5...
hope it's help you
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