Question

the speed of car of 500 kg increased from 20m/s to 40m/s how much work was done by the engine of the car​

Answer 1

AnSweR⬇️

Given,

m=500g

U=20m/s

$\: \: \: \: \: \: \: \: \: \: {v²-u² = 20s}$

$\: \: \: \: \: \: \: \: {s = \frac {20×20}{2×10} = 20m}$

F=ma

$\Large\orange {\bf{m \frac {∆V}{t}}}$

$= 500 × \frac {20}{2} = {\sf{5000N}}$

$\Large\purple{\bf{w = f.x}}$

$= 5000×20$ ➝ 10000 grams

Weight = $\fbox\red{100kg}$

Hope It Helps You ✌️