Question

the speed of electromagnetic wave in a medium whose dielectric constant is 2.25 and relative permeability is 4 is equal to

Answer 1

Hi,

Answer:

The speed of the electromagnetic wave in a medium is 1 * 10⁸ m/s.

Explanation:

Given data:

Relative permeability, µr = 4

Dielectric constant or Permitivity of the medium, εr = 2.25

To find: speed of electromagnetic wave in the medium, “v”

Let the permeability of the vacuum or free space, µo = 4π * 10⁻⁷ H/m

And,

The permitivity of vacuum or free space, εo = 8.85 * 10⁻¹² F/m

Now, the speed of the electromagnetic wave is given by the formula  

v = 1 / √[ µo µr εo εr]  

∴ v

= 1 / √[ 4π * 10⁻⁷ * 4 * 8.85 * 10⁻¹² * 2.25]

= 1 / √[1000.404 * 10⁻¹⁹]

= 1 / [31.62 * 3.162 * 10⁻¹⁰]

= 1 / [100.01 * 10⁻¹⁰]

= 0.0099 * 10¹⁰

= 0.99 * 10⁸ m /s

≈ 1 * 10⁸ m/s

Hope this helps!!!!

Answer 2

Answer:

Here the answer is 1×10^8