Question

The speed of light in a certain material is 50% of its speed in a vacuum. What is the refractive index of this material?

Answer 1

Answer:

Given -

• v = 50% c ( c speed of light in vacuum )

To find -

• Refractive index of this material.

Solution -

Definition of refractive index (n) .

$\\ \\ \sf \: n = \dfrac{c}{v} \\ \\ \\ \implies \sf \: n = \dfrac{c}{50\%} \\ \\ \\ \implies \sf \: c = 2.0$

Therefore, the refractive index of the material is 2.0.

Answer 2

The refractive index of the given material is 2.

Given,

v = 50% c

where v is the speed of light in the given material

and c is the speed of light in vacuum

To Find,

Refractive index of this material

Solution,

Refractive index can be defined as "a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density"

Mathematically, the refractive index 'n' is given by:

n = c/v

where v is the speed of light in the given material

and c is the speed of light in vacuum

We have been given that v = 50% c

⇒ v = 0.5 c

Therefore, refractive index,

⇒ n = c / v

⇒ n = c / 0.5 c

⇒ n = 1/0.5

⇒ n = 2

Therefore, the refractive index of this material is 2

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