Physics, asked by choudhuryaakash00, 10 months ago

The speed of light in air is 3*10^8 ms^-1 the speed of light in water is 2.26*10^8ms^-1. Find the refractive index of water. Find the refractive index of material if angle of incidence of ray of light is 45° and angle of refraction in the material is 30°​

Answers

Answered by dimprajapati
5

Hola there,

Speed of light in air = 3 × 10^8

Speed of light in water = 2.26 × 10^8

Refractive index of water = Speed of light in air/speed of light in water

= (3 × 10^8)/(2.26 × 10^8)

= 1.32743363 ....Ans

Hope this helps...:)

Answered by LEGEND778
5

Answer:

1.32743363

Explanation:

Speed of light in air = 3 × 10^8

Speed of light in water = 2.26 × 10^8

Refractive index of water = Speed of light in air/speed of light in water

= (3 × 10^8)/(2.26 × 10^8)

= 1.32743363

R.I=sine of angle of incidence/sine of angle of refraction

R.I=sin45/sin30

R.I=

SIN45  

1/√2

sin 30

1/2

R.I=1.414

√2 = 1.414

pls mark as brainliest answer

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