Physics, asked by Qassim3857, 9 months ago

The speed of light in diamond is 124000km/sec.if the speed of light in air is 300000km/sec then the refractive index of diamond will be

Answers

Answered by bhagyashreechowdhury
1

If the speed of light in air is 300000 km/sec and speed of light in diamond is 124000 km/sec then the refractive index of diamond will be  2.42 .

Explanation:

  • Refractive Index or the index of refraction of a material “n” is defined as the measure of bending of light ray when passing from one medium to another medium.  
  • It is determined as the ratio of velocity of light in air or vacuum denoted as “c” to the velocity of light in a specific material denoted as “v” i.e.,  

                                            n = c/v ….. (i)

It is given,

The speed of light in Diamond, c = 124000 km/sec

The speed of light in Air, v = 300000 km/sec

Thus, by substituting the given values in eq. (i), we get

The refractive index of diamond will be,

= 300000 / 124000

= 300 / 124

= 2.42

----------------------------------------------------------------------------------------

Also view:

The speed of light in a given medium is 2/3rd of its speed in vacuum the absolute refractive index of the medium equals to

https://brainly.in/question/3812593

When a Ray of light enters a medium of refractive index new it is observed that the angle of refraction is half of the angle of incidence is then angle of incidence is?

https://brainly.in/question/5169852

A critical angle for a medium is 60 degree . The refractive index of the medium is ___?

https://brainly.in/question/7997328

Answered by harendrakumar4417
0

0.413

Explanation:

  • Refractive index is a property of medium which helps us find the deflection of light beams or rays.
  • Usually air has a refractive index of 1 and other materials have more than 1.
  • Velocity and refrative index can related by the abow formula,\frac{v1}{v2} =\frac{\alpha1 }{\alpha2 },where \alpha is the refractive index of the material.
  • So by this relation we can find the refractive index of unknown materials.
  • According to the given data speed in different medium are given so we can find the refractive index .

\frac{124000}{300000} =\frac{\alpha1 }{1}

\frac{31}{75} =\alpha1\\  \\\alpha 1=0.413

Hence the refractive index of the material is 0.413.

Similar questions