Chemistry, asked by kritikasharma606, 11 months ago

the speed of light is 3.0 into 10 to the power 8 metre per second calculate the distance covered by the light in 2.00 NS​

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Answered by pranayasahu
1

Answer:

1 mm=10^-6 km 1pm=10^-15 km 1NS=10^-9 second separation = speed × time:- distance= 3×10^8×2×10^-9:- distance=6×10^-1 meter.

The speed of light in vacuum, normally signified c, is an all inclusive physical consistent critical in numerous zones of material science.

Its correct esteem is 299,792,458 meters for each second. Physicists frequently utilize the letter c to mean the speed of light in void space (vacuum).

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Answered by manas7083
2

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