Physics, asked by chiranjeev2193, 10 months ago

The speed of object undergoing uniform circular motion is 4m/s. The magnitude change in velocity during 0.5 sec is also 4m/s. Find minimum possible centripetal acceleration

Answers

Answered by sashikantchoubey

Answer:

change in velocity / time , 4/0.5= 8

Explanation:

so the required centripetal acceleration is 8 m/sec^2

Answered by knjroopa

Explanation:

Given The speed of object undergoing uniform circular motion is 4 m/s. The magnitude change in velocity during 0.5 sec is also 4 m/s. Find minimum possible centripetal acceleration

Given speed of an object undergoing uniform circular motion is 4 m/s and the magnitude change in velocity is also 4 m/s.
So magnitude of change in velocity is
Δν = √ν^2 + ν^2 - 2ν^2 cos theta
= 2 ν sin theta / 2
Δν = 2 x 4 sin theta / 2
Or theta / 2 = π / 6
Or theta = π / 3
So the value of theta is π / 3 and value of μo = 4 m/s.
Now a r = V^2 / R
ar = 4^2 / R
Now we know that in 0.5 secs it should move at 4 m/s.
So 0.5 x 4 = 2 m
So the distance will be 2 m
So π / 3 x R = 2
Or R = 6 / π
Now a r = 16 / R
Or a r = 16 / 6 / π
Or a r = 16 π / 6
Or a r = 8 π / 3
Therefore centripetal acceleration will be 8 π / 3