Question

The speed of object undergoing uniform circular motion is 4m/s. The magnitude change in velocity during 0.5 sec is also 4m/s. Find minimum possible centripetal acceleration

Answer 1

Answer:

change in velocity / time , 4/0.5= 8

Explanation:

so the required centripetal acceleration is 8 m/sec^2

Answer 2

Explanation:

Given The speed of object undergoing uniform circular motion is 4 m/s. The magnitude change in velocity during 0.5 sec is also 4 m/s. Find minimum possible centripetal acceleration

• Given speed of an object undergoing uniform circular motion is 4 m/s and the magnitude change in velocity is also 4 m/s.
• So magnitude of change in velocity is  
• Δν = √ν^2 + ν^2 - 2ν^2 cos theta
•       = 2 ν sin theta / 2
•      Δν = 2 x 4 sin theta / 2
•  Or theta / 2 = π / 6
•      Or theta = π / 3
• So the value of theta is π / 3 and value of μo = 4 m/s.
• Now a r = V^2 / R
•           ar = 4^2 / R
• Now we know that in 0.5 secs it should move at 4 m/s.
• So 0.5 x 4 = 2 m
• So the distance will be 2 m
•             So π / 3 x R = 2
•            Or R = 6 / π
•           Now a r = 16 / R
•            Or a r = 16 / 6 / π
•          Or a r = 16 π / 6
•         Or a r = 8 π / 3
• Therefore centripetal acceleration will be 8 π / 3

Reference link will be

https://brainly.in/question/17084517