Question

the speed of projectile at max height is half of its initial speed the angle of projection is

Answer 1

Answer:

60 degree

Explanation:

Hi!

Let us assume the speed to be u by which the ball is thrown

So at max-height, we know that the speed of the ball in y component becomes 0. So Uy=0

Hence we can only compare the speed in the x-direction.

So according to question

Ux=U/2

We know that Ux is Ucos@

Ucos@=U/2

Canceling out U we have

cos@=1/2

The value of @ at cos@=1/2 is 60 degree

I hope it helps!