the speed of solid sphere OF ROLLING DOWN FROM REST WITHOUT SILDING ON AN INCLINED PLANE OF VERTICAL HEIGHT H IS
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Initial velocity (u) = 0 m/s
Distance covered (s) = H metres
Acceleration (a) = g m/s^2 (for vertical motion)
According to the third equation of motion,
v^2 = u^2 + 2as
So, v^2 = 0 + 2gH
So, v^2 = 2gH
Taking Square roots on both sides,
So, v = √(2gH) => This is the answer.
If you want, you can substitute the value of g,
(g = 9.8 m/s^2) but it's not compulsory.
So, v = √[(2)(9.8)(H)]
So, v = √(19.6H)
Distance covered (s) = H metres
Acceleration (a) = g m/s^2 (for vertical motion)
According to the third equation of motion,
v^2 = u^2 + 2as
So, v^2 = 0 + 2gH
So, v^2 = 2gH
Taking Square roots on both sides,
So, v = √(2gH) => This is the answer.
If you want, you can substitute the value of g,
(g = 9.8 m/s^2) but it's not compulsory.
So, v = √[(2)(9.8)(H)]
So, v = √(19.6H)
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