The speed of sound in air at 0 °C is 332 m/s. If it increases at the rate of 0.6 m/s per degree, what will be the temperature when the velocity has increased to 344 m/s? (Ans: 200 °C).Solve the example.
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Increased velocity = 344m/s - 332m/s = 12m/s
Temperature = 12m/s ÷ 0.6m/s = 20℃
It is the answer...
Answered by
6
"The velocity increase in sound in air medium when the temperature increases from 0°C to 7°C = 344 - 332 = 12 m/s
Given:
The sound velocity air rises by 0.6 m/s for 1°C rise in temperature.
Since, the temperature should rise for 1 m/s increase in sound velocity present in air is 1/0.6°C.
Hence, the temperature rise for 12 m/s rise in sound velocity in air medium = 12/0.6°C = 20°C.
Therefore, the temperature at which the velocity of air becomes 344 m/s = 20°C
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