The speed of sound in air at 0 degree Celsius is 332m/'s. If it increases at the rate of 0.6m/'s per degree what will be the temperature when the velocity has increased to 344m/s
Answers
Answered by
2
increase in speed=(344-332)m/s=12m/s
increase in 0.6m/s=1°
increase in 1m/s=1°/0.6
increase in 12m/s=(1/0.6×12)°=20°
hence increase in temperature=0°+20°=20°
increase in 0.6m/s=1°
increase in 1m/s=1°/0.6
increase in 12m/s=(1/0.6×12)°=20°
hence increase in temperature=0°+20°=20°
Similar questions