Question

The speed of sound in air at 0degree celcius is 332 m/s.If it increases at the rate of 0.6 m/s per degree ,What will be the temperature when the velocity has increased to 344 m/s

Answer 1

The speed of sound in air at 0℃ = 332m/s

If it increases at the rate of 0.6m/s per degree,

Speed at x℃ = (332 + 0.6x)℃

Thus 344 = 332 + 0.6x

344 - 332 = 0.6x

12 = 0.6x

x = 12/ 0.6 = 20℃

Temperature is 20℃

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Answer 2

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$\huge \sf{Solution - }$

Given,

Speed at 0°C = 332m/s

Let the increased temperature be x°C

If speed increases at the rate of 0.6

m/s per degree

Then speed,
= (332 + 0.6x)°C

Also given,

the final velocity at x temperature

= 344m/s

So,

$344 = \: (332 \: + \: 0.6x) \\0.6x = 344 - 332 \\ 0.6 x= 12 \\ x = 20$

Hence, the temperature will be 20°C.

Hope it helps !