Question

The speed of sound in air is 332m/s if the volume of nitrogen (moleculer wt.28)and oxygen (mol. Wt. 32)in air in ratio 4:1 then find out the speed of sound in oxygen

Answer 1

The speed of sound in air is 332 m/s.If volumes of nitrogen (molecular wt. 28) and oxygen (molecular wt. 32) in air are in ratio 4:1, then find out the speed of sound wave.

ANSWER -315 m/s

Answer 2

Answer:

The speed of sound in oxygen will  be 315 m/s

Step-by-step explanation:

Given,

Speed of sound in air = 332 m / s

Ratio of volume of Nitrogen and oxygen = 4 : 1

So,

Molecular weight = ( 4 * 28 + 1 * 32 ) / 5  

= 144 / 5

= 28.8

Now Since we know,

$\frac{V_{1}}{V_{2}}=\sqrt{\frac{M_{2}}{M_{1}} }$

Substituting the know values,

$\frac{332}{V_{2}}=\sqrt{\frac{32}{28.8}$

$\frac{332}{V_{2}}=\sqrt{1.11}$

$\frac{332}{V_{2}}=1.05$

$V_{2}$ = 332 / 1.05

$V_{2}$ = 315 m /s

Hence,

The speed of sound in oxygen will  be 315 m/s