Question

the speed of the body which is moving with constant accelaration from 5m/s to 15m/s in 5sec. Find the displacement?

Answer 1

first to find acceleration
v=u+at
15=5+a×5
a=15-5/5
a=2m/s^2

second equation

v^2=u^2+2as
15^2=5^2+2×2×s
225=25+4s
4s=225-25
s=200/4
s=50m

's' is denoted by distance, so the distance travelled is 50m.

Hope it will help you

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

u = 5 m/s

v = 15 m/s

t = 5 s

${\boxed{\sf\:{Using\;1^st\;equation\;of\;Motion}}}$

v = u + at

${\boxed{\sf\:{Substitute\;the\;value}}}$

15 = 5 + a × 5

5a = 10

a = 2

${\boxed{\sf\:{Using\;2^nd\;equation\;of\;Motion}}}$

v² = u² + 2as

Put the values

225 = 25 + 2 × 2 × s

4s = 200

$\tt{\rightarrow s=\dfrac{200}{4}}$

s = 50 m

Therefore,

Displacement is 50 m