The speed of the car in straight road increases from 4 me' to 8 ms' in 0.2 second
Calculate the force involved mass the car is 500 kg.
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Explanation:
v1 = 4m/s
v2 = 8 m/s
t = 0.2s
F = ?
m= 500kg
F= ma
F= m(v2-v1)
t
F=500(8-4)
0.2
F = 10000N
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