Physics, asked by anaghamaluzz9, 1 month ago

The speed of the car in straight road increases from 4 me' to 8 ms' in 0.2 second
Calculate the force involved mass the car is 500 kg.

Answers

Answered by ushnazahid

1

Explanation:

v1 = 4m/s

v2 = 8 m/s

t = 0.2s

F = ?

m= 500kg

F= ma

F= m(v2-v1)

t

F=500(8-4)

0.2

F = 10000N

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