Science, asked by reenajayant2006, 8 months ago

the speed of the car reduces from 15 m/s to 5 m/s over a displacement of 10 m​

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Answered by arenarohith
2

Answer:

Here, initial velocity u=15m/s and final velocity v=5m/s

Using the formula, v2=u2+2aS ⇒52=152−2a(10) or a=−10m/s2 (negative sign indicates the car is deaccelerating)

Answered by abhishekprvt
0
the speed of the car reduces from 15 m/s to 5 m/s over a displacement of 10 m
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