Question

The speed of the component waves of a stationary wave is 1200 m/s. If the distance between consecutive antinode and node is 1 m, then frequency of standing wave will be ..........(a) 300 Hz(b) 400 Hz(c) 600 Hz(d) 1200 Hz

Answer 1

Answer:

Distance between consecutive antinode and node is

λ/4

Given, v = 1200m/s

λ/4 = 1m ----> λ = 4m

v = fλ

f = v/λ = 1200/4 = 300Hz

f = 300Hz

Option (A)