Question

the speed of the electron in the first orbit of the hydrogen atom in the ground state is(C is the velocity of light) in cm/sec​

Answer 1

Hii Dear,

◆ Answer -

v = 1/137 c

● Explanation -

Speed of electron in nth orbit of atom is given by -

v = Ze² / 2εnh

For 1st orbit of H, Z = 1 & n = 1,

v = 1 × (1.6×10^-19)^2 / (2 × 8.85×10^-12 × 1 × 6.6×10^-34)

v = 2.19×10^6 m/s

Ratio of speed of this electron with speed of light will be -

v/c = 2.19×10^6 / 3×10^8

v/c = 0.0073

v = 0.0073 c

v = 1/137 c

Therefore, speed electron in 1st orbit of hydrogen will be c/137.

Best luck ..

Answer 2

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