Question

The speed of the light in a diamond is 1,24,000km/s. Find the refractive index of diamond if the
speed of light in air is 3,00,000 km/s.

Answer 1

n = c/v
c = speed of light in air/vacuum
v = speed of light in given medium ( diamond in this case )
Thus, n = 300000/124000
n = 300/124 = 2.42


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Answer 2

Answer:

. The speed of light in diamond is 1.24 x 108 m/s. What is its refractive index?

. The speed of light in diamond is 1.24 x 108 m/s. What is its refractive index?{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}

. The speed of light in diamond is 1.24 x 108 m/s. What is its refractive index?{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}Assuming the speed of light in the reference medium is 3 x 108:

. The speed of light in diamond is 1.24 x 108 m/s. What is its refractive index?{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}{\displaystyle n={\frac {v_{1}}{1.24\times 10^{8}}}}Assuming the speed of light in the reference medium is 3 x 108:{\displaystyle n={\frac {3\times 10^{8}}{1.24\times 10^{8}}}={\frac {3}{1.24}}\approx 2.42}{\displaystyle n={\frac {3\times 10^{8}}{1.24\times 10^{8}}}={\frac {3}{1.24}}\approx 2.42}.

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