The speed of the scooter moving with uniform
celeration of 4ms becomes 20 msata
certain time. What will be the speed of the
So , when has covered a distance of
112
m e that time?
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Answer:
Curved surface area of frustum = 3055 m²
Step-by-step explanation:
Let's assume that the big radius is R and small radius is r
Now, R = 30/2 = 15m
r = 6/2 = 3m
h = 24.
The slant height of the frustum cone is given by following equation
= √(h² + (R - r)²)
= √(24² + (15 - 3)²)
= 27 m. (approx.)
Now,
Curved surface area of frustum
= π(R + r)l
= 22/7 × ( 30 + 6 ) × 27
= 22/7 × 36 × 27
= 3055 m²
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