The speed of the vehicle of mass 0.5g increase from 36 Km/hr to 72 Km/hr . Calculate the increase in its kinetic energy.
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initial velocity= 36 x 5/18 = 10m/s
initial kinetic energy = mv²
=0.5/10³ x 10²=
5/100 joules
= 0.05joules
final velocity= 72 x 5/18 = 20m/s
final Velocity= 0.5/10³ x 20²
= 2/10 joules
= 0.2 joules
increase= 0.2 -0.05 joules
= 0.15 joules.
initial kinetic energy = mv²
=0.5/10³ x 10²=
5/100 joules
= 0.05joules
final velocity= 72 x 5/18 = 20m/s
final Velocity= 0.5/10³ x 20²
= 2/10 joules
= 0.2 joules
increase= 0.2 -0.05 joules
= 0.15 joules.
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