Question

The speed of the wave 360m/s and is 500 Hertz if the phase difference between two neighbouring particles is 60 degree then what will be path difference​

Answer 1

Answer:

k = speed/frequency

=> k =36/50  

now phase difference = (2∏/k )* path difference  

60 = (360/36) * 50 * path difference  

distance bewtween two nearest points i

= path difference

= 6/50 metre