Question

the speed of the weight just before hitting the beam is in ft/second approximately if the distance of fall is 25ft​

Answer 1

the speed of the weight just before hitting the beam is in ft/sec if the distance of fall is 25 ft.

solution : initial velocity of the ball, u = 0 ft/s [ as ball are falling from a certain height ]

accerating acting on the ball, a = g = 32 ft/s²

initial height of the ball, h = 25 ft  

using formula, s = ut + 1/2 at²

⇒ 25ft = 0 × t + 1/2 × 32 ft/s² × t²

⇒ t² = 25/16 = (5/4)²

⇒ t = 5/4 = 1.25 sec

now we have to find the velocity of the ball.

   use , v = u + at

⇒ v = 0 + (-32ft/s²)(1.25 sec) = - 40 ft/s

therefore the speed of the ball just before the hitting the beam is 40ft/s