Question

the speed of train is decreasing from 90 kmph to 36 kmph to 2by 1 by 2 minutes as it is approaching the station find its retardation

Answer 1

90kmph= 25m/s

36kmph = 10m/s

2 min= 120 sec

deceleration =(v-u)/t

                      =(25-10)/120

                      = (1/8) m/s^2

                      =(0.125) m/s^2