the speed time graph of a ball of mass 30 g moving along a straight line is shown in the figure below calculate the opposing force that brings the ball to rest
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Answered by
39
u= 50 m/s
v= 0 m/s
t= 4 seconds
a= (v-u)/t
a= -50/4 = -12.5
F= ma
F= 0.04* -12.5
negative sign it is a retarding force
v= 0 m/s
t= 4 seconds
a= (v-u)/t
a= -50/4 = -12.5
F= ma
F= 0.04* -12.5
negative sign it is a retarding force
Answered by
19
Answer:u=50m/s
V=0
T=4s
A=?
By putting 1st eq. of motion
V=u+at
0=50+4a
-50=4a
A=
-12.5m/s²
F=?
By putting 2nd law of newton
F=ma
F=0.03×(-12.5)
F=-0.375N
Explanation:
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