The speed-time graph of a car is shown
in figure. The distance travelled by the
car in 10 seconds will be
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Explanation:
(a)
The total number of divisions on horizontal axis for 2 s is 5.
The total number of divisions on vertical axis for 2 m/s is 3.
The total displacement of the car during these two seconds will be given as the area under all these squares.
The area under the (3×5) squares is given as:
A15=2×2 = 4
So, the area under one small square is :
A1=154
Now, the area under the graph for 4 sec is:
the number of squares under the graph is :
n=57 small squares + 6 half small squares
So, total number of squares =60.
So, the distance traveled by the car is the area under the curve.
S=60×154
S=16 m
(b)
The car moves under the uniform motion after the instant t=6 s because after this instant, the speed of the car becomes constant......
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