Question

The speed time graph of a car is shown in the figure which of the following statement

Answer 1

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(a)The total number of divisions on horizontal axis for 2 s is 5.

The total number of divisions on vertical axis for 2 m/s is 3.

The total displacement of the car during these two seconds will be given as the area under all these squares.

The area under the (3×5) squares is given as:

A 15 =2×2 = 4

So, the area under one small square is :

A1=4/15

Now, the area under the graph for 4 sec is:

the number of squares under the graph is :

n=57 small squares + 6 half small squares

So, total number of squares =60.

So, the distance traveled by the car is the area under the curve.

S=60× 4/5

S=16 m

(b)

The car moves under the uniform motion after the instant t=6 s because after this instant, the speed of the car becomes constant.

Answer 2

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==> (a)

The total number of divisions on horizontal axis for 2 s is 5.

The total number of divisions on vertical axis for 2 m/s is 3.

The total displacement of the car during these two seconds will be given as the area under all these squares.

The area under the (3×5) squares is given as:

A15=2×2 = 4

So, the area under one small square is :

A1= 4/15

Now, the area under the graph for 4 sec is:

the number of squares under the graph is :

n=57 small squares + 6 half small squares

So, total number of squares =60.

So, the distance traveled by the car is the area under the curve.

S=60× 4/15

S=16 m

(b) The car moves under the uniform motion after the instant t=6 s because after this instant, the speed of the car becomes constant.

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