The speed time graph of a car of 1000kg mass is given . On the basis of this, answer the following question.
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Given , mass of the car (m) = 1000 kg
(i) As, shown in graph,
Distance covered in first 2 sec
= Area of Δ inscribed in first 2 s.
= 1 / 2 × base × height
= 1 / 2 × 2 ×15 = 15 m
(ii) Force (F) = mass (m) × acceleration (a)
Time taken by force to stop car = 6 - 5 = 1
second
Initial velocity (i.e. velocity at B) = 15 m/s
Final velocity (at point C) = 0 m/s
using equation v = u + at
a = (v-u) / t = (0 -20) / 0.02 = -15 m/s2
(-ve sign indicates that it is retardation )
Force applied by brakes = 1000 × -15 = -15000 N
= - 15 KN
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