the speed time graph of a particle moving along a fixed direction is shown in the figure the distance travelled by the particle between t is equal to 2 second and t is equal to 6 second is
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36 m
Explanation:
the speed time graph of a particle moving along a fixed direction is shown in the figure the distance travelled by the particle between t is equal to 2 second and t is equal to 6 second is
as per graph
acceleration from 0 to 5 sec is same
a = (12 -0)/(5-0) = 2.4 m/s²
V at 2 sec = 0 + 2.4*2 = 4.8 m/s²
V at 5 sec = 12 m/s²
Using V² - U² = 2aS
Distance covered from 2 to 5 sec = (12² - (4.8)²)/(2*2.4)
= 30 - 4.8
= 25.2 m
acceleration from 5 to 10 sec
= (0 -12)/(10 - 5) = -2.4 m/s²
Velocity at 6 sec = 12 -2.4*(6-5) = 9.6 m/s
Distance covered from 5 to 6 sec = (9.6² - 12²)/(2*(-2.4))
= -19.2 +30
= 10.8 m
Total distance from 2 to 6 sec
= 25.2 + 10.8
= 36 m
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