Physics, asked by ameensha, 6 months ago

The speed time graph of abody of mass 50kg in shown in the figure calaculate the force acting on the body a)from 0 to 4 sec b) from 4 to ​

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Answered by john332
1

Answer:

we know

slope of velocity vs time graph gives acceleration

from 0-4 s

acceleration =(20-20)/(4-0)

=0

so force acting from 0-4 s =m^a=50*0=0N

now

for 4-6 sec

acceleration =(0-20)/(6-4)

=-10m/s²

force =m*a=50*(-10)=-500N

Answered by sohamsangit9
1

Answer:

areemereko request bhejo na...

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