Question

The speed v of a particle moving along a straight

line, when it is a distance x from a fixed point on

the line is given by v² = 108 x – 9 x². Then magnitude

of its acceleration when it is at distance 3 meter

from the fixed point is-

[1] 9 m/s² [2] 18 m/s²

[3] 27 m/s² [4] None of these​

Answer 1

Answer:

seriously don't know yrrr....

Answer 2

Answer:

On differentiating with respect to time :

2.v. (dv/dt)=108.(dx/dt)-18.x.(dx/dt)

But a = dv/dt

v = dx/dt

So 2va = 108v - 18xv (equation 2)

Thus 2a = 108 - 18x

So if distance (x) = 3 :

2a = 108 - 54

a = 27