Question

The speeds of train is measured by 5 students. The
result of measurements are 10.2 m/s, 10.4 m/s, 10.6m/s
9.8 m/s. 10.8 m/s. What is the percentage error in
the measurement of its speed​

Answer 1

Answer:

Percentage uncertainty in 10d = 1 mm. 200 mm ... thickness of the rim of the coin and not its average thickness. ... a) Horizontal component of velocity, uh = 12 cos 30 ° = 10.4 m s−1. [1].

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Answer 2

Answer:

The percentage error is 0.05%.

Explanation:

Here,

The minimum value is denoted by $x_{m}$.

The number of measurements is denoted by N.

The average of all values is denoted by x.

The sum of all variables is denoted by S.

Now,

By the equation,

$x=\frac{S}{N} \\x=\frac{10.2+10.4+10.6+9.8+10.8}{5} \\x=10.36m/s$

Then,

percentage error  $=\frac{x-x_{m} }{x}$

                              $=\frac{10.36-9.8}{10.36}$

                              $=$ 0.05%

So, the percentage error is 0.05%.