Math, asked by Anishka786, 4 months ago

The sphere of mass 1000kg are having distance of 0.5 between centres . The force of gravitational is ?​

Answers

Answered by Anushka786
3

Given :

 \tt \ mass_1 \:  = mass_2 = 1000kg

 \tt \: distance = 0.5m

To Find :

 \tt \: gravitational \: force

Solution :

\tt\:F = GM/d²

  • Here G is the Gravitational constant whose value is 6.67 × 10-¹¹

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According to question :-

 \tt\implies \: f = GMm/d²

 \tt\implies \: f \:  = (6.67 \times  {10}^{ - 11} \times  1000)  \div  {(0.5)}^{2}

 \tt\implies \: f = (6.67 \times  {10}^{ - 11}  \times  {10}^{6} ) \div \: 0.25

 \tt\implies \: f \:  = (6.67 \times  {10}^{( - 11 + 6)} ) \div 0.25

 \tt\implies \: f \:  = 6.67 \times  {10}^{ - 5} \div 0.25

 \tt\implies \: 2.67 \times  {10}^{ - 5}

∴ The answer is 2.67 × 10–5 ...

 \small{\underline{\boxed{\tt{\green{f = 2.67 \times  {10}^{ - 5}}} }}}

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Anishka786: nice answer and thank you for your help!
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