The spin magnetic moment of Fe in [FeF₆]³⁻ is *
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Answer:
The magnetic moment of `K_3[Fe(CN)_6]` is found to be `1.7 B.M`. ... The magnetic moment of `K_3[Fe(CN)_6]` is found to be `1.7 B.M`.
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Explanation:
oxidation state of Fe in [FeF6]³- = x + (-6) = -3
= x= 6-3
x= +3
Fe³+ configuration is = [Ar]3d5
so, the no. of unpaired electron in Fe is 5.
Magnetic moment, μ= n(n+2)
= 5(5+2)=
35
=5.92 BM
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