The spin only magnetic moment value of Cr(CO)6 is what?
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In Cr(CO)6, the central Cr atom is d2sp3 hybridised. Hence all the electrons in its valence shell is paired. So it has net magnetic moment zero (0 BM).
The spin-only magnetic moment is given by: μ S = 2.0023 √ S ( S + 1 ) where g = 2.0023 is the gyromagnetic ratio and S is the total spin of all unpaired electrons in the system. If there are none...then μ S = 0 .
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