Question

The splash of sound was here 5.35sec weafter droping a stone into a well 122.5m deep velocity of sound air is?

Answer 1

Answer:

by putting the formula v2=u2+at

Answer 2

Answer:

Time taken by the stone to reach the water,

$t = \sqrt{ \frac{2h}{g} } = \sqrt{ \frac{2 \times 122.5}{9.8} } = 5 \: sec$

So, the remaining time =5.35−5=0.35 sec

0.35sec was taken by sound to travel 122.5 m

Hence, speed =

$= \frac{122.5}{0.35} = 350 m/s$