Question

the spring constant of the spring shwn in fig is 250 N/m. find the maximum compression of the spring

Answer 1

hey, friend,
the answer is 
by using conservation of momentum
      mu+Mv=(m+M)v'
      (m=5kg
        M=1kg
         u=initial velocity=15 of m
                    and M initial velocity is zero as it is at rest)
      from here we get v=25/2
       now from energy conservation, we get 
        1/2(m+M)v'^2=1/2kx^2
        we get answer
        Xmax=((15)^1/2)/2

Answer 2

Answer:

K.E. of mass = Elastic Potential Energy of spring