Question

The spring in Figure 6.5 stretches from 10 cm to 22 cm when a force of 4 N is applied. If it obeys Hooke’s
law, its total length in cm when a force of 6 N is applied is,
a. 28
B. 42
C .50
D .56
E. 100

Answer 1

Answer:

a.28

Explanation:

When 4n force acts then spring increass by 12cm.It means,In force increase 12 divided by 4 or 3cm.so,6n will increase 18cm.hence,total length of string will be 28cm.

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