Question

the spring is stretches from 10 cm to 22 cm when a force of 4 n is applied. if it obeys hooke’s law, its total length in cm when a force of 6 n is applied, (chose the correct option from the following) * A) 18 B) 28 C) 50 D) 56​

Answer 1

Answer:

B) 28

Explanation:

22cm-10cm=12cm

then,

12cm/x = 4/6

so multiply 12 with 6, and 4 with x then you get

4x = 72

so to get rid of four just simply divide by four then...

x = 18

then add 10 to 18 because that was the original spring's length

x=18+10

x=28  

done!