Question

the sqares of two consecutive integers differ by 23,then find the smallest integer​

Answer 1

Answer:

Let the required integers be x and (x+1).

Atq,

$\: \: \: \: \: \: {(x + 1)}^{2} - {x}^{2} = 23 \\ = > {x}^{2} + 2x + 1 - {x}^{2} = 23 \\ = > 2x + 1 = 23 \\ = > 2x = 23 - 1 \\ = > 2x = 22 \\ = > x = \frac{22}{2} \\ = > x = 11$

Hence, required integers are 11 and (11+1) = 12

Original answer :

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Answer 2

Answer:

let the required integers be ×

ATQ

$x + 1 - x = 23$

$x + 2x + 1 - x = 23$

$2x + 1 = 23$

$2 x = 23 - 1$

$2x = 22$

$x = 2$

$x = 11$

Hence, required integers are 11 (11+1)=12

Explanation:

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