Question

the square - 2D + 3 is equal to zero

${d}^{2} - 2d + 3 = 0$

Answer 1

$\bold{Answer :}$

Now,

d² - 2d + 3 = 0

or, d² - 2d = - 3

or, d² - 2d + 1 = - 3 + 1

or, (d - 1)² = - 2

or, (d - 1)² = [√(- 2)]²

or, (d - 1)² = √2 i², where i = √(- 1)

or, d - 1 = ± i √2

or, d = 1 ± i √2

∴ the required solution be

d = (1 + i √2), (1 - i √2)

#$\bold{MarkAsBrainliest}$