Question

the square ABGH and ADEF are drawn on the sides AB and AD of a parallelogram ABCD prove angle FAH is equal to angle ABC

Answer 1

To prove :∠FAH=∠ABC
Proof,
AD=BC and AB=DC,∠ABC=∠ADC and ∠DCB=∠BAD(Opposite sides and angles of a parallelogram are equal)
In a square all angles are equal so,
∠BAH=90⁰
Now,∠BAH+∠FAH=180°[L.P]
so,∠FAH=90°
Again,
∠FAD+∠DAB=180°[L.P]
∠DAB=∠DCB=90°
∠ABG+∠ABC=180°[L.P]
∠ABC=∠ADC=90°
We found that ∠ABC=90° Therefore ∠FAH=∠ABC=90°
Hence,verified

Answer 2

Answer:

this the answer and explanation