Question

The square of (4x-3y) is​

Answer 1

Answer:

${(4x-3y)}^{2} \\ {16x }^{2} + {9y}^{2} - 2 \times 4 x\times 3y \\ \\ {16x }^{2} + {9y}^{2} - 24xy$

Answer 2

$(4x-3y)^2$

∴ We'll solve it by the identity  $(a-b)^2=a^2+b^2-2ab$

So, it will be $\tt{16x^2+9y^2-24xy}$