Question

The square of a number added to 2 times the no is 80 . find the no​

Answer 1

Let the number be x.

Therefore, according to the given condition, the equation will be-

${x}^{2} + 2x = 80$

Or,

${x}^{2} + 2x - 80 = 0$

Or,

${x}^{2} - 8x + 10x - 80 = 0$

Or,

$x(x - 8) + 10(x - 8) = 0$

Or,

$(x + 10)(x - 8) = 0$

Therefore,

Either x+10=0 or, x-8=0

So,

$x + 10 = 0$

Or,

$x = - 10$

Also,

$x - 8 = 0$

Or,

$x = 8$

Therefore,

The possible numbers are -10 and 8.

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Answer 2

Answer:

the numbers are -10 and8 .

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