Question

The square of a number is decreased by 15. This value is twice the original number. Find the number(s).

Answer 1

Step-by-step explanation:

let the no. be x

ATQ

x^2-15=2x

x^2-2x-15=0

x^2-5x+3x-15=0

x(x-5)+3(x-5)=0

(x-5) (x+3)=0

x=5

x=-3

Answer 2

Answer:

refer to the above attachment for the solution