The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?
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the numbers is = X
Square of the number = X²
equal to 10 less than 7 time = 7X -10
X² = 7X-10
X²-7X+10 = 0
X² -2X-5X + 10 = 0
(X-2) (X-5) = 0
X = 2 or X = 5
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