Math, asked by anandhusheenkumar, 2 months ago

The square of a term of the sequence 2,6,10, .... is 900. What is the term position?​

Answers

Answered by snehitha2
11

Answer:

The required answer is 8th term.

Step-by-step explanation:

Given :

The square of a term of the sequence 2, 6, 10, ... is 900.

To find :

the term position

Solution :

The given sequence is Arithmetic Progression since each term is obtained by adding a constant to the preceding term.

In the given sequence,

first term, a = 2

common difference, d = 6 - 2 = 4

______________________

The square of a term is 900.

Let the term be 'x'.

x² = 900

x = √900

x = 30

______________________

nth term of an A.P is given by,

 \bf a_n = a + (n-1)d

Substitute,

30 = 2 + (n – 1)(4)

30 – 2 = (n – 1)(4)

28 = 4n – 4

4n = 28 + 4

4n = 32

n = 32/4

n = 8

Therefore, 8th term is 30.

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