Question

The square of A varies directly as the cube of B. B varies directly as the square root of c.
The value of C when A - 4 is 81. Find C when A = 3.
​

Answer 1

Answer:

According to question let, A=K

C

3

B

where K is a constant and A=3,B=256,C=2 satisfies the equation, So

3=K

2

3

256

=K

8

16

=2K

K=

2

3

So

A=

2C

3

3

B

Now for A=24,C=

2

1

we have,

24=

2.

2

1

.

2

1

.

2

1

3

B

B

=

3

24.2.

2

1

.

2

1

.

2

1

=

24

48

=2

B=2

2

=4