Question

the square of an integer is 7 more than 6 times the integer. Find the integer.

Answer 1

Answer:

let the integer be x

x² = 6x+7

x²-6x-7=0

x²-7x+x-7=0

x(x-7)+1(x-7)

(x+1)(x-7)

x=7

so integer is 7.

Answer 2

Answer:

7

Step-by-step explanation:

Let the integer be x

A.T.Q

x^2 = 6x+7

x^2 -6x -7 = 0

Now we split -6x

x^2 +x -7x -7 = 0

x(x+1)-7(x+1) = 0

(x-7)(x+1) = 0

So either of the two is zero

if x+1 = 0 then x=-1 but that doesn't fit in in the question

so x-7 = 0

x=7

The integer is 7